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Molecular mass of a gas is 78 . Its density at `98 .^(@)C` and 1 atm will beA. `200 g L^(-1)`B. `2 . 56 g L^(-1)`C. `256 g L^(-1)`D. `78 g L^(-1)` |
Answer» Correct Answer - B P = 1 atm, `T = 98^(@)C+273 = 371 K, M = 78g mol^(-1)` `R = 0.0821" L atm K"^(-1)mol^(-1)` PM=dRT or `d=(PM)/(RT)=(1xx78)/(0.0821xx371)=2.56 g L^(-1)` |
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