InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
Molecular orbital theory for o2, n2 ,f2 |
| Answer» Electronic configuration of nitrogen (Z = 7) is 1s2 2s2 2p3. Since nitrogen atom has 7 electrons, the molecular orbitals of nitrogen molecule (N2) has 14 electrons which are distributed as below : Molecular orbital energy level diagram of N2 molecule • Bond order = (8 2)/2\xa0= 3 (N ≡ N) • Absence of unpaired electrons showed that N2 molecule is diamagnetic. MOED of \'O2\' : Electronic configuration of Oxygen (Z = 8) is 1s2 2s2 2p4 . Since Oxygen atom has 8 electrons, the molecular orbitals of Oxygen molecule (O2) has 16 electrons, which are distributed as below : Molecular orbital energy level diagram of O2 • Bond order = (10 - 6)/2 = 2(O = O) • Presence of two unpaired 6 electrons (π*\xa02p1y π*2p1z,) showed that O2 molecule is paramagnetic.\xa0Read more on Sarthaks.com - https://www.sarthaks.com/535006/give-the-molecular-orbital-energy-diagram-of-n2-and-o2-write-the-bond-order-of-n2-and-o2 | |