1.

Moles of KHC_(2)O_(4) (potassiumacid oxalate) required to reduce 100 mL of 0.02M KMnO_(4) in acidic medium (to Mn^(2+)) is

Answer»

`0.002`
`0.005`
`0.001`
`0.007`

SOLUTION :EQ. `KHC_(2)O_(4)` = eq. `KMnO_(4)`
`nxx2=0.1xx0.02xx5impliesn=0.005`


Discussion

No Comment Found