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Moment of a force of magnitude 20 N acting along positive x-direction at point (3m,0,0) about the point (0,2,0) (in N-m) is

Answer» <html><body><p>20<br/>60<br/><a href="https://interviewquestions.tuteehub.com/tag/40-314386" style="font-weight:bold;" target="_blank" title="Click to know more about 40">40</a><br/>30</p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/torque-1422441" style="font-weight:bold;" target="_blank" title="Click to know more about TORQUE">TORQUE</a>, `tau=rxxF` <br/> `=[(0-<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)hat(i)+(2-0)hat(j)+(0-0)hat(k)]<a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a>[20 hat(i)]` <br/> `=[3 hat(i)+2hat(j)]xx[20 hat(i)]=-40 hat(k)`.</body></html>


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