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Moment of inertia of a circular wire of mass M and radius R about is its diameter is |
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Answer» Solution :(i) Given Data: M = 500 G = 0.5 KG, `R = 10 cm = 10 xx 10^(-2) m` `"Moment of inertia of disc about diameter" =Id=(1)/(4)MR^(2)` `Id=(1)/(4) xx 0.5 xx 0.1 kg m^(2)` (ii) APPLY a parallel axes theorem, moment of inertia of the disc about a TANGENT to the disc and parallel to the diameter of the disc `=(1)/(4)MR^(2)+MR^(2)=(5)/(4)MR^(2)=(5)/(4) xx 0.5 xx 0.1` `=0.0625 kg m^(2)` (iii) Moment of inertia of the disc about an axis passing through the centre of disc and perpendicular to the plane of the disc `=(1)/(2)MR^(2)=(1)/(2) xx 0.5 xx 0.1=0.025 kg m^(2)` |
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