Saved Bookmarks
| 1. |
Moment of inertia of a disc of radius R about a diametric axis is 35 "kg m"^(-2). The MI of the disc about a parallel axis at a distance R//2 from the centre is |
|
Answer» `31.25 "kg-m"^(2)` `I=I_(V)+md^(2)=(ma^(2))/(2)+md^(2)""(because a=R,d=R)` `rArr` Moment of inertia `= (3)/(2) ma^(2)=(3)/(2)(25)` `:.` Moment of inertia `=(75)/(2)=37.5 "kg m"^(-2)`. |
|