Moment of inertia of a ring of mass M and radius R about an axis passing through the centre and perpendicular to the plane is I. What is the moment of inertia about its diameter?

Moment of inertia of a ring of mass M and radius R about an axis passi

1.	Moment of inertia of a ring of mass M and radius R about an axis passing through the centre and perpendicular to the plane is I. What is the moment of inertia about its diameter?
Answer» I `(I)/(2)` `(I)/(SQRT2)` `I + MR^(2)` Solution :Moment of inertia of the RING of mass M and radius R about an axis passing through the CENTRE and PERPENDICULAR to the plane , `I = MR^(2) "" … (i)` Moment of inertia of the ring about its diameter `I_("diameter") = (MR^(2))/(2) = (1)/(2) (MR^(2)) = (I)/(2) ""` (Using (i))