InterviewSolution
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InterviewSolution
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Moment of inertia of a solid sphere about its diameter is I . If that sphere is recast into 8 identical small spheres, then moment of inertia of such small sphere about its diameter isA. `I//8`B. `I//16`C. `I//24`D. `I//32` |
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Answer» Correct Answer - D `"M = 8 m " therefore m=(M)/(8)` Volume of big sphere = Volume of 8 spheres `(4pi)/(3)R^(3)=8xx(4pi)/(3)r^(3)` `R = 2 r` `therefore " " r = (R )/(2)` `I_(1)=(2)/(5)mr^(2)` `= (2)/(5)mr^(2)` `= (2)/(5)xx(M)/(8)xx((R )/(2))^(2)` `= (2)/(5)MR^(2)xx(1)/(8)xx(1)/(4)` `I_(1)=I xx(1)/(32)`. |
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