1.

Moment of inertia of a straight wire about an axis perpendicular to the wire passing through one of its end is I. Now the same wire is bent into a ring of two turns , then the moment of inertia would be

Answer»

`((pi^(2))/(3))L`
`((pi^(2))/(12))l`
`((3)/(16pi^(2)))l`
`((3)/(4PI^(2)))l`

Answer :C


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