1.

Moment of inertia of a uniform rod of length L and mass M , about an axis pasing through L/4 from one end and perpendicular to its length is

Answer»

`(7)/(36) ML^2`
`(7)/(48) ML^2`
`(11)/(48) ML^2`
`(ML^2)/(12)`

Solution :APPLYING theorem of PARALLEL AXES ,
`I = I_(0) + M((L)/(4))^(2) = (ML^2)/(12) + (ML^2)/(16) = (7)/(48) ML^2`


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