1.

Momentum of a lighter and a heavier mass are equal.Which one of them has a greater kinetic energy?

Answer»

Solution :Let MASS of the LIGHTER body =m and its velocity =v , mass of the HEAVIER body= M and its velocity =V
Given ,MV =MV .
Now, the KINETIC energy of the lighter body , `K_l =1/2 mv^2` and the kinetic energy of the heavier body, `K_h =1/2 MV^2`
`therefore (K_l)/(K_h) =(1/2 mv^2)/(1/2 MV^2) = (m^2v^2)/(m) xx(M)/(M^2V^2)=M/mgt 1 [because mv =MV]`
So, the kinetic energy of the lighter body is greater than that of the heavier body.


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