Saved Bookmarks
| 1. |
Momentum of a lighter and a heavier mass are equal.Which one of them has a greater kinetic energy? |
|
Answer» Solution :Let MASS of the LIGHTER body =m and its velocity =v , mass of the HEAVIER body= M and its velocity =V Given ,MV =MV . Now, the KINETIC energy of the lighter body , `K_l =1/2 mv^2` and the kinetic energy of the heavier body, `K_h =1/2 MV^2` `therefore (K_l)/(K_h) =(1/2 mv^2)/(1/2 MV^2) = (m^2v^2)/(m) xx(M)/(M^2V^2)=M/mgt 1 [because mv =MV]` So, the kinetic energy of the lighter body is greater than that of the heavier body. |
|