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Momentumof `gamma` - ray proton of energy 3 eV in kg-m/s will beA. `1.6 xx 10^(-19)`B. `1.6 xx 10^(-21)`C. `1.6 xx 10^(-24)`D. `1.6 xx 10^(-27)` |
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Answer» Correct Answer - C Energy of X-ray `= 3 xx 10_(3) eV` `lamda=(lamda_(C))/(epsilon)=(12400eV A^(@))/(3 xx10^(3)eV)=(12.4)/(3)A^(@)` momentum `(P) =(lamda)/(lamda)=(lamda xx 3)/(12.4 xx 10^(-10))` `= 1.6 xx 10_(-24) kg m//s` |
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