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Mother,Father and Son line up at random for a family picture.E : son on one end, F:Father in middle. Find P(E/F). |
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Answer» Solution :SUPPOSE A,B,C denote the mother, the father and the son respectively. Then S ={ABC,ACB,BAC,BCA,CAB,CBA} `rArr` n(S) = 6 E = {CAB,CBA,ABC,BAC}, F={ABC,CAB} `rArr` n(F)=2 Also,`EnnF`={ABC,CAB}`rArr` n`(EnnF)` = 2 therefore`P(EnnF)`=2/6 and P(F) =2/6 `rArr` P(E/F) = `(P(EnnF))/P(F))`=1 |
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