InterviewSolution
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‘Mr. Kasam runs a small business of making earthen pots. He makes certain number of pots on daily basis. Production cost of each pot is Rs. 40 more than 10 times total number of pots, he makes in one day. If production cost of all pots per day is Rs. 600, find production cost of one pot and number of pots he makes per day. |
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Answer» Let Mr. Kasam make x number of pots on daily basis. Production cost of each pot = Rs. (10x + 40) According to the given condition, x(10x + 40) = 600 ∴ 10x2 + 40x = 600 ∴ 10x2 + 40x- 600 = 0 ∴ x2 + 4x – 60 = 0 …[Dividing both sides by 10] ∴ x2 + 10x – 6x – 60 = 0 ∴ x(x + 10) – 6(x + 10) = 0 ∴ (x + 10) (x – 6) = 0 By using the property, if the product of two numbers is zero, then at least one of them is zero, we get ∴ x + 10 = 0 or x – 6 = 0 ∴ x = – 10 or x = 6 But, number of pots cannot be negative. ∴ x = 6 ∴ Production cost of each pot = 7(10 x + 40) = Rs. [(10×6)+ 40] = Rs.(60 + 40) = Rs. 100 Production cost of one pot is Rs.100 and the number of pots Mr. Kasam makes per day is 6. |
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