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Mrinalini and Samyukta can work together to paint half of a wall in 14 days. Working separately, Mrinalini would need four times the time taken by the Samyukta to complete it. In how many days can the Samyukta paint the entire wall alone?1. 302. 283. 424. 35 |
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Answer» Correct Answer - Option 4 : 35 Given : Mrinalini and Samyukta can paint half of the wall in 14 days Mrinalini need 4 times more time than Samyukta Concept used : Working efficiency is inversely proportional to time taken Total work = person's efficiency × Number of days he takes for work Calculations : Half the work will be completed in 14 days Full work will be completed in 28 days Total work = 28 units Now, Let the efficiency of Mrinalini be 'x' unit per day So the efficiency of Samyukta will be '4x' per day Mrinalini and Samyukta per day work = x + 4x = 5x units So, (5x) × 28 = 28 units ⇒ 5x = 28 /28 ⇒ x = 1/5 units Samyukta's per day work = 4x ⇒ 4 × (1/5) = 4/5 units Total days of working of Samyukta = 28/(4/5) ⇒ 35 days ∴ Samyukta will complete the work in 35 days |
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