mu_(0) and epsilon_(0) denote the permeability and permittivity of free space, the dimensions of mu_(0) epsilon_(0)are

mu_(0) and epsilon_(0) denote the permeability and permittivity of fre

1.	mu_(0) and epsilon_(0) denote the permeability and permittivity of free space, the dimensions of mu_(0) epsilon_(0)are
Answer» `[LT^(-1)]` `[L^(-2)T^(-2)]` `[M^(-1)L^(-3)T^(-2)]` `M^(-1)L^(-3)A^(2)]` Solution :The speed of light in vaccum is given by `C= (1)/(SQRT(mu_(0)epsilon_(0))` or `mu_(0)epsilon_(0)= (1)/(c^(2)) :. [mu_(0)epsilon_(0)] = (1)/([LT^(-1)]^(2))= [L^(-2)T^(2)]`