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Multiply a monomial by a monomial.(i) 6x, 4(ii) -3x, 7y(iii) -2m2, (-5m)3(iv) a3, – 4a2b(v) 2p2q3, -9pq2 |
Answer» (i) 6x × 4 = (6 × 4) (x) = 24x (ii) -3x × 7y = (-3 × 7) (x × y) = -21xy (iii) (-2m2) × (-5m)3 = -2m2 × (-)3 (53 (m)3) = -2m2 × (-125m3) = (-) × (-)(2 × 125)(m2 × m3) = + 250 m5 = 250 m5 (iv) a3 × (-4a2 b) = (-4) × (a3 × a2) × (b) = -4a5b (v) (2p2q3) × (-9pq2) = (+) × (-) × (2 × 9) (p2 × p(q3 × q2)) = -18p3q5 |
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