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Multiply: i) \( (4-i)(3-5 i) \) ii) \( (4+ i )(3- i ) \) |
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Answer» (i) \((4 - i) (3 - 5i)\) \(= 12 + 5i^2 -3i - 20i\) \(= 7 - 23i\) (\(\because i^2 = -1\)) (ii) \((4 + i)(3 - i)\) \(= 12 - i^2 + 3i - 4i\) \(= 13 - i\) |
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