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मूल्यांकन कीजिए `sin[2cos^(-1)(-(3)/(5))]` |
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Answer» माना `cos^(-1)(-(3)/(5))=theta`, जहाँ `theta=[0, pi]` तब `" "cos theta=-(3)/(5)` चूँकि `" "theta in [0,pi],` तब `sin theta gt 0` `therefore" "sin theta =sqrt(1-cos^(2)theta)` `=sqrt(1-(-(3)/(5))^(2))=sqrt(1-(9)/(25))` `=sqrt((25-9)/(25))=sqrt((16)/(25))=(4)/(5)` |
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