1.

मूल्यांकन कीजिए `sin[2cos^(-1)(-(3)/(5))]`

Answer» माना `cos^(-1)(-(3)/(5))=theta`, जहाँ `theta=[0, pi]`
तब `" "cos theta=-(3)/(5)`
चूँकि `" "theta in [0,pi],` तब `sin theta gt 0`
`therefore" "sin theta =sqrt(1-cos^(2)theta)`
`=sqrt(1-(-(3)/(5))^(2))=sqrt(1-(9)/(25))`
`=sqrt((25-9)/(25))=sqrt((16)/(25))=(4)/(5)`


Discussion

No Comment Found