InterviewSolution
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InterviewSolution
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मूल्यांकन कीजिए `sin{(pi)/(3)-sin^(-1)(-(1)/(2))}` |
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Answer» माना `sin[(pi)/(3)-sin^(-1)(-(1)/(2))]` `=sin[(pi)/(3)-{-sin^(-1).(1)/(2)}].` `" "[because sin^(-1)(-x)=-sin^(-1)x]` `=sin[(pi)/(3)+sin^(-1)(sin.(pi)/(6))]` `" "[because (pi)/(6) in [-(pi)/(2),(pi)/(2)]]` `=sin[(pi)/(3)+(pi)/(6)]` `=sin.(pi)/(2)=1.` |
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