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Mv²/r centripilalforce(derivation)​

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Answer:

CONSIDER a body with mass m moving about a circular path of radius r at VELOCITY v.

If the body commences its rotation at the top of the CIRCLE in the illustration above, its velocity vector will be pointing, say, to the left. Once the body reaches the BOTTOM of the circle, the vector will have reversed its direction completely - therefore, the acceleration of the body during this period will be v−−vt=2vt. The velocity is constant, and so t=xv, where x is the displacement of the body. This will be EQUAL to 2r (the diameter of the motion).

Simplifying this, we have that the centripetal acceleration is equal to 2v⋅v2r=2v22r=v2r

Assuming that the mass of the body is invariant, we can apply Newton’s second law of motion to find that F=ma=mv2r. This force is causing the circular motion, and acts towards the centre of rotation.



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