InterviewSolution
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InterviewSolution
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`MX_(2)` dissociates into `M^(2+)` and `X^(-)` ions in an aqueous solution, with a degree of dissociation `(alpha)` of 0.5. The ratio of solution to the value of depression of freezing point in the absence of ionic dissociation is |
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Answer» Correct Answer - 2 `MX_(2)hArr M^(2+)+2X^(-)` `m_(0)(1-alpha) " " m_(0)alpha " " 2m_(0)alpha , m=m_(0)(1+2alpha)` `therefore m=m_(0)(1+2xx0.5)=2m_(0)` (as given) `((-Delta T_(f))_("observed"))/((-Delta T_(f))_("undissociated"))=i=(m)/(m_(0))=2` |
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