N_(2) + 3H_(2) rarr 2NH_(3), Delta H = - 46K. Cals. From the above reaction, heat of formation of ammonia is

N_(2) + 3H_(2) rarr 2NH_(3), Delta H = - 46K. Cals. From the above rea

1.	N_(2) + 3H_(2) rarr 2NH_(3), Delta H = - 46K. Cals. From the above reaction, heat of formation of ammonia is
Answer» SOLUTION :`Delta H _(3) + Delta H _(2) // 2-3 Delta H _(1) //2`