1.

`N_(2)` exerts a pressure of 0.987 bar. The mole fraction of `N_(2)` ia `(K_(H)=74.48 k `bar)A. `7.648 xx 10^(-3)`B. `9.87 xx 10^(-5)`C. `1.3 xx 10^(-5)`D. `2.6 xx 10^(-5)`

Answer» Correct Answer - C
`P_(N2)=K_(H) xx X_(N2)`
`:. X_(N2)=P_(N2)/K_(H)=(0.987"barr")/(76480"bar")=1.29 xx 10^(-5)`


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