1.

N_(2(g))+3H_(2(g)) hArr 2NH_(3(g)) , For this equilibrium reaction at given temperature find relation between K_p and K_c

Answer»

Solution :At GIVEN temperature, this equilibrium reaction `N_(2(g)) + 3H_(2(g)) hArr2NH_(3(g))` all reactant and product in GASEOUS phase.
At given temperature,
Partial pressure of `N_2=p_(N_2)`
Partial pressure of `H_2=p_(H_2)`
Partial pressure of `NH_3=p_(NH_3)`
`K_p=(p_(NH_3))^2/((p_(N_2))(p_(H_2))^3)`
but p=cRT = (mol `L^(-1)` ) RT
`K_p=([NH_3]^2(RT)^2)/{{[N_2]RT}[H_2]^3(RT)^3}`
`THEREFORE K_p=[NH_3]^2/([N_2][H_2]^3)(RT)^2/((RT)(RT)^3)`
but `[NH_3]^2/([N_2][H_2]^3)=K_c`
For this equilibrium , `K_p ne K_c` may be `K_p LT K_c`
`DELTAN`=2-(1+3)=-2
`K_p = K_c(RT)^(-2)`


Discussion

No Comment Found