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N_(2(g))+3H_(2(g)) hArr 2NH_(3(g)) , For this equilibrium reaction at given temperature find relation between K_p and K_c |
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Answer» Solution :At GIVEN temperature, this equilibrium reaction `N_(2(g)) + 3H_(2(g)) hArr2NH_(3(g))` all reactant and product in GASEOUS phase. At given temperature, Partial pressure of `N_2=p_(N_2)` Partial pressure of `H_2=p_(H_2)` Partial pressure of `NH_3=p_(NH_3)` `K_p=(p_(NH_3))^2/((p_(N_2))(p_(H_2))^3)` but p=cRT = (mol `L^(-1)` ) RT `K_p=([NH_3]^2(RT)^2)/{{[N_2]RT}[H_2]^3(RT)^3}` `THEREFORE K_p=[NH_3]^2/([N_2][H_2]^3)(RT)^2/((RT)(RT)^3)` but `[NH_3]^2/([N_2][H_2]^3)=K_c` For this equilibrium , `K_p ne K_c` may be `K_p LT K_c` `DELTAN`=2-(1+3)=-2 `K_p = K_c(RT)^(-2)` |
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