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`N_(2)H_(4)`, Hydrazine a rocket fuel can be produced according to the following rection : `CINH_(2) + 2NH_(3) rarrN_(2)H_(4) + NH_(4)CI` When `1000 g CINH_(2)` is reacted with excess of `NH_(3),473 g N_(2)H_(4)` is produced. What is the `%` yield of the reaction. |
Answer» Correct Answer - `76.12%` `ClNH_(2)+2NH_(3)rarrN_(2)H_(4)+NH_(4)Cl` `(1000)/(51.5)`mole excess `=19.417` `19.417` mole `%` yield `= (14.781)/(19.417)xx100=76.125%` |
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