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`N_(2)O_(3)` dissociates into `NO` and `NO_(2)`. At equilibrium pressure of `3 atm` , all three gases were found to have equal number of moles in a vessel. In another vessel, equimolormixture of `N_(2)O_(3), NO` and `NO_(2)` are taken at the same temperature but at an initial pressure of `9 atm` then find the partial pressure of `NO_(2)` (in `atm`) at equilibrium in second vessel! `N_(2)O_(3)(g) hArr NO(g) + NO_(2) (g)` |
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Answer» Correct Answer - 2 `N_(2)O_(3)(g)hArrNO(g) + NO_(2)(g) , K_(P) = 1` `{:("Initial",3,3,3),("Pressure",,,),(at eq.,3+P,3-P,3-P):}` `K_(P) = ((3-P)^(2))/((3+P)) = 1` Solving this `P = 1 atm` |
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