N_(2)O_(4) is dissociated to 33% and 50% at total pressure P_(1) and P_(2)atm respectively. The ratio of (P_(1))/(P_(2)) is :

N_(2)O_(4) is dissociated to 33% and 50% at total pressure P_(1) and P

1.	N_(2)O_(4) is dissociated to 33% and 50% at total pressure P_(1) and P_(2)atm respectively. The ratio of (P_(1))/(P_(2)) is :
Answer» `(7)/(4)` `(7)/(3)` `(8)/(3)` `(8)/(5)` Solution :`underset(1-alpha)underset(1)(N_(2)O_(4(g))) harr underset(2alpha)underset(0)(NO_(2(g)))` `K_(P)=((""^(n)NO_(2))^(2))/(""^(n)N_(2)O_(4)) XX [(P)/(epsilon n)]^(1)` For 33% dissociation `K_(P)=((2 xx 33)^(2))/(67) xx [(P_(1))/(133)]^(1)` …...(1) For 50% dissociation `K_(P)=((2 xx 50)^(2))/(50) xx ((P_(2))/(150))^(1)` `:. (P_(1))/(P_(2))=(133 xx 67 xx (2 xx 50)^(2))/((2 xx 33)^(2) xx 150 xx 50)=(8)/(3)`