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N_(2)O_(5) is more acidic than N_(2)O_(3). |
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Answer» Solution :Since the oxidation state of N is +5 in `N_(2)O_(5)and+3" in "N_(2)O_(3)`, therefore, `N_(2)O_(5)` can accept electrons more readily than `N_(2)O_(3)` and hence `N_(2)O_(5)` is a stronger ACID than `N_(2)O_(3)`. Alternatively, `N_(2)O_(5)andN_(2)O_(3)` dissolve in `H_(2)O` forming `HNO_(3)andHNO_(2)` respectively.  Due to higher oxidation state of +5 of N in `HNO_(3)` than +3 in `HNO_(2),NO_(2)` pulls the electrons of the O-H in `HNO_(3)` more strongly than NO pulls the electrons of the O-H bond in `HNO_(2)`. In other WORDS, `HNO_(3)` RELEASES a proton more releases a proton more reaidily than `HNO_(2)` and hence `HNO_(3)orN_(2)O_(5)` is a stronger acid than `HNO_(2)or N_(2)O_(3)`. |
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