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N-factor for the following reaction is FeS_(2)toFe_(2)O_(3)+SO_(2) |
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Answer» 8 `underset(2x=4)(2FE^(2+))overset(0)tounderset(2x=6)(Fe_(2)^(3+)+2e^(-)]n=(2)/(2)=1` `{:(underset(2x=-2)(S_(2)^(2-))toundersetunderset(2x=18)(2x-8=0)(2SO_(2))+10e^(-)]n=10` Total n factor `=10+1=11` |
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