1.

N guavas are distributed among 10 boys. The same no. of guavas are distributed among 13 boys. The same exercise is done with 52 boys. What should be the minimum value of N required to distribute, so that no guava is left?1). 1302). 5203). 2604). 1040

Answer»

The MINIMUM no. of GUAVAS required is the LCM of 10, 13 and 52.

10 = 2 × 5

13 = 1 × 13

52 = 2 × 2 × 13

LCM of 10, 13 and 52 = 2 × 13 × 2 × 5 = 260


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