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N molecules each of mass m of gas A and 2 N molecules each of mass 2m of gas B are contained in the same vessel which is maintined at a temperature T. The mean square of the velocity of the molecules of B type is denoted by `v^(2)` and the mean square of the x-component of the velocity of a tye is denoted by `omega^(2)`. What is the ratio of `omega^(2)//v^(2) = ?`A. 2B. 1C. `(1//3)`D. `(2//3)` |
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Answer» Correct Answer - 4 `V_(rms)=sqrt((3RT)/(M_(w)))` `V_(rms)=sqrt((3RT)/(mN_(a)))` `V^(2)_(rms) propto (1)/(m)` `(V^(2)_(rmsA))/(V^(2)_(rms B)) = (m_(B))/(m_(A))` `(3W^(2))/(V^(2))=(2m)/(m)` `(W^(2))/(V^(2))=(2)/(3)` |
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