InterviewSolution
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InterviewSolution
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`n` moles of gas in a cylinder under a piston is transferred infinintley slowly from a state with a volume of `V_(0)` and a pressure `3 P_(0)` to a state with a volume of `3 V_(0)` and a pressure `P_(0)` as shown in Fig. The maximum temperature that gas will reach in this process is A. `(P_(0) V_(0))/(nR)`B. `(3 P_(0) V_(0))/(nR)`C. `(4 P_(0) V_(0))/(nR)`D. `(2 P_(0) V_(0))/(nR)` |
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Answer» Correct Answer - C c. `(P - P_(1))/(P_(1) - P_(2)) = (V - V_(2))/(V_(1) - V_(2))` `(P - P_(1)) (V_(1) - V_(2)) = (V_(1) - V_(2)) = (V - V_(1)) (P_(1) - P_(2))` `(P - 3 P_(0)) (V_(0) - 3 V_(0)) = (V - V_(0)) (3P_(0) - P_(0))` `(P - 3 P_(0)) (- 2 V_(0)) = (V - V_(0)) (2 P_(0))` `- 2 V_(0) P + 6 P_(0) V_(0) = 2 V P_(0) - 2 P_(0) V_(0)` `2 V P_(0) + 2 V_(0) P - 8 P_(0) V_(0) = 0` `V P_(0) + (V_(0) nRT)/(V) - 4 P_(0) V_(0) = 0` `V^(2) P_(0) - 4 P_(0) V_(0) + V_(0) nRT = 0` `T = (P_(0) (V^(2) + 4 V V_(0)))/(V_(0) nR)` For maximum of minimum value of `T`, `(dT)/(dV) = - 2V + 4 V_(0) = 0 implies V = 2 V_(0)` `(d^(2) T)/(dV^(2)) = -2` It is negative so `T` is maximum at `V = 2 V_(0)` `T_(max) = (P_(0) (- V_(0)^(2) + 8 V_(0)^(2)))/(V_(0) nR) = (4 P_(0) V_(0))/(nR)` |
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