N2+3H2 -- 2NH3calculate enthalpy change if bond enthalpy forN -N =946

1.	N2+3H2 -- 2NH3calculate enthalpy change if bond enthalpy forN -N =946 H-H=435 N-N=389
Answer» The Enthalpy Change during the reaction N2+3H2 -- 2NH3 is 41.5 KJ/mol The Enthalpy change or HEAT of reaction- It is the amount of heat released or absorbed by the reactants, to form 1 mole of product , at constant pressure. Bond Enthalpy- The amount of heat STORED in between atoms of a molecule. It is the amount of ENERGY required to break the bond between the atoms of that molecule. The Enthalpy change of a reaction = (SUM of Bond enthalpies of products) - (Sum of bond enthapies of reactants) For reaction, 1/2 N2+3/2 H2 -- NH3 {3 (389) - [1/2 (946) + 3/2 (435) ] } KJ/mol =1167 - 473 - 652.5 = 41.5 KJ/mol

N2+3H2 -- 2NH3calculate enthalpy change if bond enthalpy forN -N =946 H-H=435 N-N=389

Answer»

The Enthalpy Change during the reaction

N2+3H2 -- 2NH3 is 41.5 KJ/mol

The Enthalpy change or HEAT of reaction- It is the amount of heat released or absorbed by the reactants, to form 1 mole of product , at constant pressure.
Bond Enthalpy- The amount of heat STORED in between atoms of a molecule.
It is the amount of ENERGY required to break the bond between the atoms of that molecule.
The Enthalpy change of a reaction = (SUM of Bond enthalpies of products) - (Sum of bond enthapies of reactants)
For reaction, 1/2 N2+3/2 H2 -- NH3 {3 (389) - [1/2 (946) + 3/2 (435) ] } KJ/mol =1167 - 473 - 652.5 = 41.5 KJ/mol