N2(g)+3H2(g)→2NH3(g);ΔH=−22kcalActivation energy, Ea for the give – InterviewSolution

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1.	N2(g)+3H2(g)→2NH3(g);ΔH=−22kcalActivation energy, Ea for the given reaction is 70 kcal. Find the activation energy for 2NH3(g)→N2(g)+3H2(g) in kcal.
Answer» $N_{2} (g) + 3 H_{2} (g) \to 2 N H_{3} (g); Δ H = - 22 k c a l$ Activation energy, $E_{a}$ for the given reaction is $70 k c a l$ . Find the activation energy for $2 N H_{3} (g) \to N_{2} (g) + 3 H_{2} (g)$ in $k c a l$ .

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