1.

N2(g) + H2(g) ⇌ NH3(g)

Answer»

Step 1:

Rewrite the given equation as it is

N2(g) + H2(g) ⇌ NH3(g)

Step 2:

Write the number of atoms of each element in the unbalanced equation on both sides of equations

ElementNumber of atoms in reactantsNumber of atoms in products
N21
H23

Step 3:

In the given equation. NH3 is a compound and it contains hydrogen element. On the left hand side there are two H atoms and on the right side 3H atoms. Equalise H atoms on both sides.

Hydrogen atomsIn reactantsIn products
Initially23
To balance3 × 22 × 3

To equalise the number of hydrogen atoms, we use 3 as the factor in the reactant and 2 as the factor in the products. Now the equation becomes

N2 + 3H2 → 2NH3

Now, count the atoms of each element on both sides of the equation. The number of atoms on both sides are equal. Hence, the balanced equation is

N2 + 3H2 → 2NH3

Now indicate the physical states of the reactants and products

N2(g) + 3H2(g) ⇌ 2NH3(g)


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