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N2+H2-NH3 jismeN2 N2 hai 50kg H2 hai 10kg to batao shidhant abhikarmak koon hai Hindi me |
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Answer» As we know that,no. of moles= MOL. wt.Wt. WEIGHT of N 2 =50kgMolecular weight of N 2 =28gNo. of moles of N 2 = 2850×10 3 =17.86×10 2 molesWeight of H 2 =10kgMolecular weight of N 2 =2gNo. of moles of N 2 = 210×10 3 =5×10 3 molesN 2 +3H 2 ⟶2NH 3 From the above reaction,1 mole of N 2 react with 3 moles of H 2 .No. of moles of H 2 required to react with 17.86×10 2 moles of N 2 =3×17.86×10 2 =5.36×10 3 molesBut only 5×10 3 moles of H 2 are available.Thus H 2 is the limiting reagent here.Now, again from the above reaction,Amount of AMMONIA formed when 3 moles of H 2 react =2 molesTherefore,Amount of ammonia formed when 5×10 3 moles of H 2 react = 32 ×(5×10 3 )=3.33×10 3 molesMolecular weight of ammonia =17gWeight of ammonia in 3.33×10 3 moles =17×(3.33×10 3 )=56.61kg.Hence the amount of NH 3 formed is 56.61kg.Explanation:OKKK |
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