

InterviewSolution
Saved Bookmarks
1. |
`Na_(2)SO_(4).xH_(2)O` has `50% H_(2)O`. Henxe, `x` is :A. `4`B. `5`C. `6`D. `8` |
Answer» Correct Answer - D `%` by `wt`. Of `H_(2)O` `=(wt. "of" H_(2)O)/("Total wt".) xx100` `50=(18x)/(142+18x)xx100` `71+9x=18x` `x=71//9=7.88~~8` |
|