Na2S2O3 + I2 gives Na2S4O6 + NaI

1.	Na2S2O3 + I2 gives Na2S4O6 + NaI
Answer» <html><body><p>+I2 = Na2S4O6+NaI <a href="https://interviewquestions.tuteehub.com/tag/balance-891682" style="font-weight:bold;" target="_blank" title="Click to know more about BALANCE">BALANCE</a> the equation by ion electron method. here we see iodine , I2 is <a href="https://interviewquestions.tuteehub.com/tag/reduced-1181337" style="font-weight:bold;" target="_blank" title="Click to know more about REDUCED">REDUCED</a> (as <a href="https://interviewquestions.tuteehub.com/tag/oxidation-588780" style="font-weight:bold;" target="_blank" title="Click to know more about OXIDATION">OXIDATION</a> number changes from 0 to -1) and <a href="https://interviewquestions.tuteehub.com/tag/sulphur-1234343" style="font-weight:bold;" target="_blank" title="Click to know more about SULPHUR">SULPHUR</a> is oxidised. ( as oxidation number of s changes from +2 to +2.5).plzzzz mark as brainlist...</p></body></html>

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