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Na2S2O3 + I2 gives Na2S4O6 + NaI |
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Answer» +I2 = Na2S4O6+NaI BALANCE the equation by ion electron method. here we see iodine , I2 is REDUCED (as OXIDATION number changes from 0 to -1) and SULPHUR is oxidised. ( as oxidation number of s changes from +2 to +2.5).plzzzz mark as brainlist... |
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