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Name one reagent or one operation to distinguish between (i) BeSO_(4) and BaSO_(4) (ii) Be(OH)_(2) and Ba(OH)_(2) (iii) Na_(2)CO_(3) and NaHCO_(3) |
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Answer» Solution :(i) WATER : `BeSO_(4)` is SOLUBLE in `H_(2)O` while `BaSO_(4)` is not (ii) Alkali : `Be(OH)_(2)` dissolves in alkali but `Ba(OH)_(2)` does not (iii) Heat : `NaHCO_(3)` on heating gives `CO_(2)` which turns lime water milky . In constrast , `Na_(2)CO_(3)` does not decompose on heating to form `CO_(2)`. |
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