Name the octants in which the following points lie:(i) (5, 2, 3)(ii) (

1.	Name the octants in which the following points lie:(i) (5, 2, 3)(ii) (-5, 4, 3)(iii) (4, -3, 5)(iv) (7, 4, -3)(v) (-5, -4, 7)(vi) (-5, -3, -2)(vii) (2, -5, -7)(viii) (-7, 2, -5)
Answer» (i) (5, 2, 3) In this case, since x, y and z all three are positive then octant will be XOYZ (ii) (-5, 4, 3) In this case, since x is negative and y and z are positive then the octant will be X′OYZ (iii) (4, -3, 5) In this case, since y is negative and x and z are positive then the octant will be XOY′Z (iv) (7, 4, -3) In this case, since z is negative and x and y are positive then the octant will be XOYZ′ (v) (-5, -4, 7) In this case, since x and y are negative and z is positive then the octant will be X′OY′Z (vi) (-5, -3, -2) In this case, since x, y and z all three are negative then octant will be X′OY′Z′ (vii) (2, -5, -7) In this case, since z and y are negative and x is positive then the octant will be XOY′Z′ (viii) (-7, 2, -5) In this case, since x and z are negative and x is positive then the octant will be X′OYZ′

Name the octants in which the following points lie:(i) (5, 2, 3)(ii) (-5, 4, 3)(iii) (4, -3, 5)(iv) (7, 4, -3)(v) (-5, -4, 7)(vi) (-5, -3, -2)(vii) (2, -5, -7)(viii) (-7, 2, -5)

Answer»

(i) (5, 2, 3)

In this case, since x, y and z all three are positive then octant will be XOYZ

(ii) (-5, 4, 3)

In this case, since x is negative and y and z are positive then the octant will be X′OYZ

(iii) (4, -3, 5)

In this case, since y is negative and x and z are positive then the octant will be XOY′Z

(iv) (7, 4, -3)

In this case, since z is negative and x and y are positive then the octant will be XOYZ′

(v) (-5, -4, 7)

In this case, since x and y are negative and z is positive then the octant will be X′OY′Z

(vi) (-5, -3, -2)

In this case, since x, y and z all three are negative then octant will be X′OY′Z′

(vii) (2, -5, -7)

In this case, since z and y are negative and x is positive then the octant will be XOY′Z′

(viii) (-7, 2, -5)

In this case, since x and z are negative and x is positive then the octant will be X′OYZ′