1.

NaOH and Na_(2)CO_(3) are dissolved in 200ml aqueous solution. Now methyl orange is added in the same solution titrated and requires 2.5ml of the same HCl. Calculate the normality of NaOH & NaCO_(3).

Answer»

`(0.5)/(200),(1.5)/(200)`
`(1.5)/(200),(0.5)/(200)`
`(0.5)/(200).(0.5)/(200)`
`(1.5)/(200),(1.5)/(200)`

Solution :Let M moles of NaOH = a, `Na_(2)CO_(3)=B`
With phenolphthalein, `eq_(HCl)` = `eq_(NaOH)+(1)/(2)eqNa_(2)CO_(3)`
`17.5xx0.1=axx1+bxx1`
With methyl organe, `eq_(HCl)=(1)/(2)eqNa_(2)CO_(3)`
`2.5xx0.1=bxx1`
`implies a=1.5,b=0.25`
implies `[NaOH]=(1.5)/(200)M=(1.5)/(200)N`
`[Na_(2)CO_(3)]=(0.25)/(200)M=(0.5)/(200)N`


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