NaOH_((aq)) + HCl_((aq)) rarr NaCl_((aq)) + H_(2)O, Delta H= -13.6 Kcal. H_(2(g)) + (1)/(2) O_(2(g)) rarr H_(2)O , Delta H = - 68 Kcal. What is hat of formation of OH^(-) ?

NaOH_((aq)) + HCl_((aq)) rarr NaCl_((aq)) + H_(2)O, Delta H= -13.6 Kca

1.	NaOH_((aq)) + HCl_((aq)) rarr NaCl_((aq)) + H_(2)O, Delta H= -13.6 Kcal. H_(2(g)) + (1)/(2) O_(2(g)) rarr H_(2)O , Delta H = - 68 Kcal. What is hat of formation of OH^(-) ?
Answer» `-54.4` KCAL `+54.4` kCal `+13.6` kCal `-13.6` kCal Solution :`NaOH + HCL rarr NACL + H_(2)O` can be written as `OH^(-) + H^(+) rarr H_(2)O, Delta H = -13.6` `Delta H = Delta H_(f_(H_(2)O)) - Delta H_(f_(OH^(-))) rArr - 13.6 = - 68- Delta H_(f_(OH^(-)))` `Deta H_(f_(OH^(-))) = -54.4` Kcal