Nazima is Fly fishing in a stream the tip of her fishing rod is 1.8 metre above the surface of the water And the fly at the end of the string rests On The Water 3.6 away and 2.4 m from a point directly under the trip of the rod assuming that the string from the tip of a rod to the fly is taught how much time does she have out if she pulls the string at the rate of 5 cm per second what will be the horizontal distance of the fly from her after to 12 seconds

Nazima is Fly fishing in a stream the tip of her fishing rod is 1.8 me

1.	Nazima is Fly fishing in a stream the tip of her fishing rod is 1.8 metre above the surface of the water And the fly at the end of the string rests On The Water 3.6 away and 2.4 m from a point directly under the trip of the rod assuming that the string from the tip of a rod to the fly is taught how much time does she have out if she pulls the string at the rate of 5 cm per second what will be the horizontal distance of the fly from her after to 12 seconds
Answer» Explanation:LET AB be the height of the tip of the fishing rod from the water surface.Let BC be the horizontal DISTANCE of the fly from the tip of the fishing rod.Then, AC is the length of the string.∴ AC 2 =AB 2 +BC 2 [ By Pythagoras theorem ]∴ AC 2 =(1.8) 2 +(2.4) 2 ∴ AC 2 =3.24+5.76∴ AC 2 =9∴ AC=3mThus, the length of the string out is 3mShe pulls the string at the RATE of 5cm/s∴ String pulled in 12 second = 12×5=60cm=0.6mLet the fly be at POINT D after 12 seconds.Length of string out after 12 second is AD.⇒ AD = AC - String pulled by Nazima in 12 seconds.⇒ AD=(3−0.6)m=2.4m⇒ In △ADB,AB 2 +BD 2 =AD 2 (1.8) 2 +BD 2 =(2.4) 2 BD 2 =5.76−3.24BD 2 =2.52∴ BD=1.587mHorizontal distance of fly =BD+1.2mHorizontal distance of fly =1.587m+1.2m∴ Horizontal distance of fly =2.79m