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(NCERT Examplar Problem) Molecular orbitals are formed by the overlap of atomic orbitals . Two atomic orbitals combine to form two molecular orbitals called bonding molecular orbital (BMO) and antibonding molecular orbital (ABMO) . Energy of antibonding orbitals is raised above the parent atomic orbitals that have combined and the energy of the bonding orbitals is lowered than the parent atomic orbitals . Energies of verious molecular orbitals for elements hybrogen to nitrogen increase in the order : sigma 1s lt sigma ^(**)1s lt sigma 2s lt sigma^(**)2s lt (pi_(2p_(x)) = pi_(2p_(y))) lt sigma2p_(z) lt (pi^(**)2p_(x) = pi^(**) 2p_(y)) lt sigma^(**) 2p_(z) and for oxygen and fluorine , order of energy of molecular orbitals is given below : sigma 1s lt sigma ^(**)1s lt sigma 2s lt sigma^(**)2s lt sigma 2p_(x) lt (pi_2p_(x) = pi_2p_(y))lt (pi^(**)2p_(x) = pi^(**) 2p_(y)) lt sigma^(**) 2p_(z) Different atomic orbitals of one atom combine with those atomic orbitals of the second atom which have comparable energies and proper orientation . Further , if the overlapping is headon, the molecular orbital is called 'sigma', (sigma) and if the overlap is lateral, the molecular orbitals is called 'pi' , (pi) . The molecular orbitalsare filled with electrons according to the same rules as followed for filling ofatomic orbitals . However, the order for filling is not Whihc of the following statements is correct ?

Answer»

In the formation of dioxygen form OXYGEN atoms, 10 molecular orbitals will be formed.
All the molecular orbitals in the dioxygen will be completely filled
Total number of bonding molecular orbitals will not be same as total number of antibonding orbitals in dioxygen.
Number of filled bonding orbitals will be same as number of filled antibonding orbitals

Solution :`O_(2)`
`sigma_((1s)/(1))^(2) sigma_((1s)/(2))^(**2) sigma_((2s)/(3))^(2) sigma_((2s)/(4))^(**2) sigma_((2p_(z))/(5))^(2) pi_((2p_(X))/(6))^(2)pi_((2p_(y))/(7))^(2)pi_((2p_(x))/(8))^(**1)pi_((2p_(y))/(9))^(**1)pi_((2p_(z))/(10))^(**0)`


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