[NCERT Exemplar)Questiits areaon S. Side of a triangle are in the5. Si

1.	[NCERT Exemplar)Questiits areaon S. Side of a triangle are in the5. Side of a triangle are in the ratio of 12 17 25 and its perimeter is 540
Answer» Ratio of the sides of the triangle = 12 : 17 : 25 Let the common ratio be x then sidesare 12x, 17x and 25x Perimeter of the triangle = 540cm 12x + 17x + 25x = 540 cm ⇒ 54x = 540cm ⇒ x = 10Sides of triangle are, 12 × 10 = 120cm 17x = 17 × 10 = 170cm 25x = 25 × 10 = 250cm Semi perimeter of triangle(s) = 540/2 = 270cm Using heron's formula,Area of the triangle = √s (s-a) (s-b) (s-c) = √270(270 - 120) (270 - 170) (270 - 250)cm2 = √270 × 150 × 100 × 20 cm² = 9000 cm²

[NCERT Exemplar)Questiits areaon S. Side of a triangle are in the5. Side of a triangle are in the ratio of 12 17 25 and its perimeter is 540

Answer»

Ratio of the sides of the triangle = 12 : 17 : 25

Let the common ratio be x then sidesare 12x, 17x and 25x

Perimeter of the triangle = 540cm

12x + 17x + 25x = 540 cm

⇒ 54x = 540cm

⇒ x = 10Sides of triangle are,

12 × 10 = 120cm

17x = 17 × 10 = 170cm

25x = 25 × 10 = 250cm

Semi perimeter of triangle(s) = 540/2 = 270cm

Using heron's formula,Area of the triangle = √s (s-a) (s-b) (s-c) = √270(270 - 120) (270 - 170) (270 - 250)cm2

= √270 × 150 × 100 × 20 cm² = 9000 cm²