InterviewSolution
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Negation of (p ∧ q) → (~ p ∨ r) is(A) (p ∨ q) ∧ (p ∧ ~ r) (B) (p ∧ q) ∨ (p ∧ ~ r)(C) (p ∧ q) ∧ (p ∧ ~ r) (D) (p ∨ q) ∨ (p ∧ ~ r) |
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Answer» Correct option: (C) (p ∧ q) ∧ (p ∧ ~ r) Since, p → q ≡ ~p ∨ q ∴ ~[(p ∧ q) → (~p ∨ r)] ≡ ~[~(p ∧ q) ∨ (~p ∨ r)] ≡ ~[(~p ∨ ~q) ∨ (~p ∨ r)] ≡ ~(~p ∨ ~q) ∧ ~(~p ∨ r) ≡ (p ∧ q) ∧ (p ∧ ~r) |
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