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Neglecting the density of air ,the terminal velocity obtained by a raindrop of radius 0.3 mm falling through air of viscosity 1.8xx10^(-5)Nsm^(-2) will be …. |
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Answer» `10.9ms^(-1)` `eta=1.8xx10^(-5)Nms^(-2)` Terminal velocity `v_(t)=(?)` `v_(t)=(2)/(9)(r^(2)g(rho-rho_(o)))/(eta)` `rho` = DENSITY of water `=10^(3)kg//m^(3)` `rho_(o)`=neglecting air density `v_(t)=(2)/(9)((9xx10^(-8))(9.8)(10^(3)))/(1.8xx10^(-5))` `=10.88` `v_(t)=10.9m//s` |
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