Neglecting the liquid-liquid junction potential, calculate the emf of the following cell at `25^(@)C` `H_(2) (1 atm)|0.5 M HCOOH|| 1M CH_(3)COOH | (1 atm) H_(2)` `K_(a) " for " HCOOH and CH_(3) COOH` are `1.77 xx 10^(-4) and 1.8 xx 10^(-5)` respectively.

Neglecting the liquid-liquid junction potential, calculate the emf of

1.	Neglecting the liquid-liquid junction potential, calculate the emf of the following cell at `25^(@)C` `H_(2) (1 atm)\|0.5 M HCOOH\|\| 1M CH_(3)COOH \| (1 atm) H_(2)` `K_(a) " for " HCOOH and CH_(3) COOH` are `1.77 xx 10^(-4) and 1.8 xx 10^(-5)` respectively.
Answer» `[H^(+)] " in " HCOOH = sqrt(C xx K_(a)) = sqrt(0.5 xx 1.77 xx 10^(-4))` `[H^(+)]` in `CH_(3)COOH = sqrt(C xx K_(a)) = sqrt(1 xx 1.8 xx 10^(-5))` `= 4.2426 xx 10^(-3)M` `E_("cell") = 0.059 log. ([H^(+)]_(RHS))/([H^(+)]_(LHS)) = 0.059 log. (4.2426 xx 10^(-3))/(0.9407 xx 10^(-2))` `= -0.0204` volt

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Neglecting the liquid-liquid junction potential, calculate the emf of the following cell at `25^(@)C` `H_(2) (1 atm)|0.5 M HCOOH|| 1M CH_(3)COOH | (1 atm) H_(2)` `K_(a) " for " HCOOH and CH_(3) COOH` are `1.77 xx 10^(-4) and 1.8 xx 10^(-5)` respectively.

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