Saved Bookmarks
| 1. |
Neon gas is generally used in the sign boards. If it emits strongly at 616 nm, calculate (a) the frequency of the emission(b) distance travelled by this radiation in 30s (c) energy of quantum (d) number of quanta present if it produces 2J of energy. |
|
Answer» Solution :`lamda = 616 nm = 616 XX 10^(-9) m` (a) Frequency, `v = (c)/(lamda) = (3.0 xx 10^(8) ms^(-1))/(616 xx 10^(-9) m) = 4.87 xx 10^(14) s^(-1)` (b) Velocity of the radiation `= 3.0 xx 10^(8) ms^(-1)` `:.` Distance travelled in `30s = 30 xx 3 xx 10^(8) m = 9.0 xx 10^(9) m` (c) `E = HV = h (c)/(lamda) = ((6.626 xx 10^(-34) Js) xx 3.0 xx 10^(8) ms^(-1))/(616 xx 10^(-9) m) = 32.27 xx 10^(-20)J` (d) No. of quanta in 2J of energy `= (2)/(32.27 xx 10^(-28)) = 6.2 xx 10^(18)` |
|